Answer: [tex]146\ cm^2[/tex]
Step-by-step explanation:
In the given figure, We have a trapezoid and a triangle sharing a common base of 14 cm.
For trapezoid,
Area =[tex]\frac{1}{2}(a+b)h[/tex], where a and b are the opposite parallel sides and h is the height.
Therefore, Area of trapezoid = [tex]\frac{1}{2}(4+14)10=(18)5=90\ cm^2[/tex]
For triangle,
The height of triangle H =18 cm - 10 cm = 8 cm
Area =[tex]\frac{1}{2}bh[/tex], where b is the base and h is the height.
Area of triangle= [tex]\frac{1}{2}\times(14)(8)=56\ cm^2[/tex]
Total area of the figure = [tex]90+56=146\ cm^2[/tex]
