Solution:
As we know that the equation of a straight line passing through a given point and having slope m is given by
[tex] (y-y_1)=m(x-x_1) [/tex]
Here we can find the slope of the line from the given points (-3,3) and (-1,-3)
Slope of the line can be found using the formula
[tex] m=\frac{y_2-y_1}{x_2-x_1}\\ [/tex]
Here the points are (-3,3) and (-1,-3) So the slope will be
[tex] m=\frac{-3-3}{-1+3}\\
\\
m=\frac{-6}{2}=-3\\ [/tex]
Hence the equation of the straight line will be
[tex] (y-3)=-3(x+3) [/tex]
or
[tex] (y+3)=-3(x+1) [/tex]
