A. y = (x+3)^2-5
B. x = -3(y+5)^2
C. y = (x-5)^2+3
D. y = (x+3)^2+5

The vertex form of the parabola:
[tex]f(x)+a(x-h)^2+k\\\\(h;\ k)-a\ vertex[/tex]
We have the coordinates of a vertex
[tex](-3;-5)\to h=-3;\ k=-5[/tex]
substitute:
[tex]y=(x-(-3))^2+(-5)=(x+3)^2-5[/tex]
Answer: A. y = (x + 3)² - 5