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a cyclist racing in the keiran is riding at the top of the track at 5m/s. the. he sprints downhill in the sprinting to the finish in 1.75s. his acceleration was 9m/s^2. what was his ending velocity at the finish line?

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Answer is: ending velocity at the finish line was 20,75 m/s.
v(initial velocity) = 5 m/s.
a = 9 m/s²; acceleration attained by the body.
t = 1,75 s; sprinting time.
Ending velocity is defined as the velocity attained by a body after completing distance at certain time interval:
v(ending velocity) = v(initial velocity) + a·t.
v(ending velocity) = 5 m/s + 9 m/s² · 1,75 s.
v(ending velocity) = 20,75 m/s.

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