Respuesta :

TheBilogis
Firstly, you need to find the x length in inches by using the Pythagorean theorem.

[tex]a^2+b^2=c^2 [/tex]
[tex]x^2+6^2=8^2[/tex]
[tex]x^2=64-36[/tex]
[tex]x= \sqrt{28}[/tex] [approx. 5.3 inches]

To find side y, 
[tex]y^2+5.3^2=7^2[/tex]
[tex]y^2=49-28.09[/tex]
[tex]y= \sqrt{20.91}[/tex] [approx 4.6 inches]

a^2 + b^2= c^2a​2​​ + b​2​​ = c​2​​ 
x^2 + 6^2= 8^2x​2​​ + 6​2​​ = 8​2​​ 
x^2 = 64- 36x​2​​ = 64 − 36 
x= \sqrt{28}x=√​28​​​ [approx. 5.3 inches]

Now

To find side y, 
y^2+5.3^2=7^2y​2​​+5.3​2​​=7​2​​ 
y^2=49-28.09y​2​​=49−28.09 
y= \sqrt{20.91}y=√​20.91​​​ [approx 4.6 inches]

I think is correct

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