(0,1) and (3,0)
You've been given the equation y = (-1/3)x + 1, so finding points for the graph is quite simple. Let's do so:
First, let's use an X value of 0 (I'm lazy and multiplying by 0 is rather simple).
y = (-1/3)x + 1
y = (-1/3)*0 + 1
y = 0 + 1
y = 1
So one of the points is (0,1)
Now let's see about doing another X value. Since the slope is -1/3 and I'm lazy I want to use an X value that is easy. And 3 would be a nice value since 3 on top and 3 on the bottom of a fraction cancel out. So let's use X = 3.
y = (-1/3)x + 1
y = (-1/3)3 + 1
y = (-3/3) + 1
y = -1/1 + 1
y = -1 + 1
y = 0
And we have another point, which is (3,0)
So two points on your line are (0,1) and (3,0).
