Velocity of Electron V1 = 1.50 Ă—10^6 m/s
Velocity of Electron V2 = 9.00 Ă— 10^6 m/s
We know the mass of electron m = 9.11 x 10^-31
Charge of the electron q = 1.60 x 10^-19
Calculating the potential energy at the two stages,
K1 = 0.5 x m V1^2 = 0.5 x 9.11 x 10^-31 x (1.50 Ă—10^6)^2 = 10.24 x 10^-19
K2 = 0.5 x m V2^2 = 0.5 x 9.11 x 10^-31 x (9.00 Ă—10^6)^2 = 368.95 x 10^-19
Change in Potential energy delta K= K2 - K1 = 358.71 x 10^-19
As we know for total energy conservation total change in energy is 0
so q x delta V + delta K = 0
delta V = - delta K / q = 358.71 x 10^-19 / 1.60 x 10^-19 = 224.19V
Potential difference for the electron to pass = 224.19V
