Respuesta :

W0lf93
We shall find the molar mass first.  
Ca5(PO4)3(OH) = (40 * 5) + 3 (31 + 4(16)) + 16 + 1 = 200 + 285 + 17 = 485 + 17 = 502. 
Percent of Calcium = 200/ 502 * 100 = 39.8%
 Percent of Phosphorus = 91/502 * 100 = 18.1%
 Percent of Hydrogen = 1/502 * 100 = 0.19%
 Percent of Oxygen = 100 - (39.8 + 18.1 + 0.19) = 41.91%

mariejoepagaduan

Tooth enamel is hydroxyapatite with the chemical formula Ca₅(Po₄)₃OH. The percent composition of the elements are:

Ca - 7.35%

Po - 92.02%

O - 0.59%

H - 0.04%

FURTHER EXPLANATION

Mass percent or percent composition is the ratio of an element's mass to the mass of the compound. It is mathematically expressed as:

[tex]mass \ \% \ of \ X = \frac{mass \ of X}{mass \ of \ compound} \times 100[/tex]

To determine the percent composition of each element in tooth enamel, we first get the mass of the compound:

[tex]mass \ of \ compound \ = (5 \times 40.078) +(12 \times 209) + \ 15.999 +1.008\\\\\boxed {mass \ of \ compound = 2725.397 \ g}[/tex]

To get the percentage composition, use the first equation and plug in the appropriate values:

  • %Ca

[tex]\% Ca= \frac{5 \times 40.078 \ u}{2725.397 u} \times 100\\\\\boxed {\% Ca= 7.35\%}[/tex]

  • %Po

[tex]\% Po= \frac{12 \times 209 \ u}{2725.397 u} \times 100\\\\\boxed {\% Po=92.02\%}[/tex]

  • %O

[tex]\% O= \frac{15.999\ u}{2725.397 u} \times 100\\\boxed {\% O=0.59\%}[/tex]

  • %H

[tex]\% H= \frac{1.008\ u}{2725.397 u} \times 100\\\boxed {\% O=0.04\%}[/tex]

LEARN MORE

  • Learn more about Mass Percentage  https://brainly.com/question/4213901
  • Learn more about Empirical formula brainly.com/question/8516072

Keywords: tooth enamel, percent composition

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