How much energy must be removed from a 500 g block of ice to cool it from 0∘c to -35 ∘c? the specific heat of ice is 2090 jkg⋅k?

Respuesta :

The quantity of heat (i.e. energy) needed to change the temperature of a substance by a certain [tex]\Delta T[/tex] is
[tex]Q=m C_S \Delta T[/tex]
where m is the mass of the block of ice, m=500 g=0.5 Kg, [tex]C_S=2090~J Kg /K[/tex] is its specific heat, and [tex]\Delta T = 35~K[/tex]. Using these data, we obtain
[tex]Q=36575~J = 36.6~kJ[/tex]
and this is the energy we must remove.