Solution:
we are given with a diagram
we have been asked to find the area of the given diagram.
Area of the diagram=Area of Triangle (ABC+DFH+GHE)+Area of Rectangle DBCE.
As we know the area of the triangle[tex] =\frac{1}{2}base*height [/tex]
Are of Rectangle [tex] =Length*width [/tex]
Substitute the values in the above formula from labelled diagram
Area of the given diagram[tex] =\frac{1}{2} (4*3+4*3+8*2)+8*3\\ [/tex]
Area of the given diagram[tex] =\frac{1}{2}*40+24=20+24=44 \ square \ Unit \\ [/tex]
