The cyclist is moving by uniformly accelerated motion, with an initial velocity of [tex]v_i=5~m/s[/tex] and an acceleration of [tex]a=9~m/s^2[/tex].
The acceleration is given by
[tex]a= \frac{v_f-v_i}{\Delta t} [/tex]
where [tex]v_f[/tex] is the final velocity and [tex]\Delta t[/tex] is the time between the end and the beginning of the motion, and in our case it is 1.75 s. Therefore, from this relationship we can find the final velocity:
[tex]v_f=v_i + a \Delta t=5~m/s+9~m/s^2 \cdot 1.75~s=20.75~m/s[/tex]
