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1. One of the substances in a new alkaline battery is composed of 63.0% manganese and 37.0% oxygen by mass. Determine the empirical formula of the compound in the battery.

Respuesta :

Divide each % value by respective atomic mass  
Mn = 63.0/54.94 = 1.1467 
O = 37/16 =2.3125 
Divide by smaller value 
Mn = 1  
O = 2.3125/1.1467 = 2 Empirical formula = MnO2
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From the steps used in calculating empirical formula, the empirical formula of the compound is MnO₂

What is empirical formula?

Empirical formula is the formula of a compound showing the simplest ratio in which the elements of the compound are combined.

How to find the empirical formula of the compound

Find the mole ratio of the elements in the compound.

  • Mole ratio =  % mass of element /relative atomic mass  

For Manganese:

Mn =  63.0/54.94 = 1.1467

For Oxygen:

O = 37/16 = 2.3125

Divide both by smaller value to get whole number mole ratios

Mn = 1.1467/1.1467

O = 2.3125/1.1467 = 2

Therefore, the empirical formula of the compound is MnO₂

Learn more about empirical formula at: https://brainly.com/question/1210188

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