A pea plant that has round seeds has the genotype Rr. It is crossed with a pea plant that has wrinkled seeds and the genotype rr. What is the probability that the offspring will have wrinkled seeds? (A) 0 percent (B) 25 percent (C) 50 percent (D) 75 percent

Respuesta :

the answer is (c) 50 percent

Answer:

Option C is correct.

Explanation:

Given the genotype of two parents-

Parent pea Plant I - Rr

Parent pea Plant II - rr

When these two parents are crossed with each other the following offspring are produced -

R r

r Rr rr

r Rr rr

 R represents the round seed and it is a dominant trait.

r represents wrinkled seed and it is a recessive trait.

From the punnet square above, it is visible that out of four offspring 2 are recessive with genotype "rr"

hence, the  probability that the offspring will have wrinkled seeds is

[tex]\frac{2}{4} * 100\\= 50[/tex]%

Option C is correct