contestada

what mass of ammonia is necessary to react with 2.1x10^24 molecules of oxygen in 4NH3+7O2=6H2O+4NO2 *Please show steps*

Respuesta :

TheSandman1337
First of all, we need to know how many moles of oxygen 2.1*10^24 molecules of oxygen are. According to the definition of Avogadro's number, 6.02*10^23 molecules are 1 mole. Thus (by proportion) the given amount is equal to:[tex] \frac{2.1*10^{24}}{6.02*10^{23}} = 3.49 [/tex] moles of oxygen (O2). By the stoicheiometry of the reaction, for every 7 moles of oxygen reacting, we need 4 moles of ammonia. Hence, we need 4/7*3.49 moles = 2 moles of ammonia. We need to calculate its weight; we know that the atomic mass of hydrogen is 1 and that the atomic mass of nitrogen is 14 (atomic and molecular masses are measured in grams). Hence, the molecular mass of ammonia (that contains 3 hydrogen atoms and a nitrogen atom) is: 3*1+1*14= 17 gr. The molecular mass of a substance is how much one mole of molecules of this substance weighs. Hence, the 2 required moles of ammonia weigh 2*17=34 gr. 34 gr of ammonia is the necessary quantity.
CintiaSalazar

Taking into account the reaction stoichiometry and the definition of Avogadro's Number, 33.87 grams of NH₃ is required to react with 2.1×10²⁴ molecules of oxygen.

Reaction stoichiometry

In first place, the balanced reaction is:

4 NH₃ + 7 O₂ → 6 H₂O + 4 NO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • NH₃: 4 moles
  • O₂: 7 moles
  • H₂O: 6 moles
  • NO₂: 4 moles

The molar mass of the compounds is:

  • NH₃: 17 g/mole
  • O₂: 32 g/mole
  • H₂O: 18 g/mole
  • NO₂: 46 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • NH₃: 4 moles ×17 g/mole= 68 grams
  • O₂: 7 moles ×32 g/mole= 224 grams
  • H₂O: 6 moles ×18 g/mole= 108 grams
  • NO₂: 4 moles ×46 g/mole= 184 grams

What is Avogadro's Number

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Amount of moles of oxygen

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of oxygen, then 2.1×10²⁴ molecules are contained in how many moles of oxygen?

amount of moles of oxygen= (2.1×10²⁴ molecules × 1 mole)÷ 6.023×10²³ molecules

amount of moles of oxygen= 3.487 molecules

Finally, 3.487 molecules of oxygen are in 2.1×10²⁴ molecules of oxygen.

Mass of NH₃ required

The following rule of three can be applied: If by reaction stoichiometry 7 moles of O₂ react with 68 grams of NH₃, 3.487 moles of O₂ react with how much mass of NH₃?

[tex]mass of NH_{3} =\frac{3.487 moles of O_{2}x 68 grams of NH_{3} }{7 moles of O_{2}}[/tex]

mass of NH₃= 33.87 grams

Finally, 33.87 grams of NH₃ is required to react with 2.1×10²⁴ molecules of oxygen.

Learn more about

the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

#SPJ2

Otras preguntas