I'm going to do elimination to find the price of one pear and one orange.
6p +5o =1.87
12p + 2o=1.90
I'm going to multiply the first equation by -2.
-12p-10o = -3.74
12p + 2o =1.90
-8o= -1.84
-1.84÷ -8= .23= o
12p + 2 (.23) = 1.90
12p + .46 = 1.90
12p = 1.44
p=.12
A pear equals .12, while an orange equals .23.
3×.12= .36
.23× 3 = .69
.69 + .36 = 1.05
It would cost $1.05.
