Respuesta :
Use Hooke's Law F=kx, where k is the spring constant and x is the displacement. Then:
[tex]x= \frac{F}{k}= \frac{88}{440} =0.2m[/tex]
[tex]x= \frac{F}{k}= \frac{88}{440} =0.2m[/tex]
The displacement of the spring will be 0.2 m. Spring displacement is the ratio of the force applied on the spring and the spring constant.
What is spring force?
The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is;
F = kx
The given data in the problem is;
F is the spring force =88 N
K is the spring constant= 440 N/m
x is the length by which spring got stretched =?
The displacement is found as;
[tex]\rm F= Kx \\\\ x= \frac{F}{K} \\\\ x= \frac{88}{440} \\\\ x= 0.2 \ m[/tex]
Hence,the displacement of the spring will be 0.2 m.
To learn more about the spring force, refer to the link;
https://brainly.com/question/4291098
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