Answer: x = 3.
Explanation:
The expression is miswritten.
I am going to try to show it correctly writen using the math editor:
[tex] log_{(4x-10)}32 = 5[/tex]
Just to be sure that it is understandable, the expression is read: logarithm base (4x - 10) of 32 equals 5.
To solve it, you take antilogarithm:
[4x - 10]^5 = 32
Now decompose 32 in 2^5
=> [4x - 10]^5 = 2^5
=> 4x - 10 = 2
=> 4x = 12
=> x = 12 / 4 = 3
Answer: x = 3
