Respuesta :

[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh\quad \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ ------\\ B=124\\ h=25.2 \end{cases}\implies V=\cfrac{1}{3}(124)(25.2)[/tex]