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The area of a playground is 255 yd^2. The width of the playground is 2 yards longer than its length. (VIEW ATTACHMENT)

The area of a playground is 255 yd2 The width of the playground is 2 yards longer than its length VIEW ATTACHMENT class=

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xanmc11
The answer is C because 15 * 17 is 255 and its two yards arpart
mathmate
Let w=width
then w-2=length
Area = w(w-2)=255
Solve for w
w^2-2w-255=0
(w-17)(w+15)=0
w=15 or w=17
Since w>length, reject w=15.
So width 17, length=15

Note: Double check if question actually says width is two yards longer than the length.