Chris practiced a total of 2 5/6 hours.
To add fractions, we need to find and convert all the number's denominators GCF, However; there is a shortcut to this problem.
Since Chris practiced 1 hour on Wednesday, we can put that to the side.
If you added the time Chris practiced on Monday and Thursday, you would get the equation: [tex]3/4 + 1/4 = ?[/tex] If you were to solve this problem, you would get the answer: [tex]4/4[/tex] which would ultimately simplify into [tex]1[/tex] Now put that hour to the side along with the hour on Wednesday.
You are now left with 1/2 an hour on Tuesday and 1/3 of an hour on Friday. We need to find the GCF of the number's denominators. The denominators would be 2 and 3 so we need to find the GCF of those numbers. The factors of two are: 2, 4, 6, 8, 10... and the factors of 3 are 3, 6, 9, 12... Among those factors, the common factor is 6. So we need the fractions 1/2 and 1/3 to have the denominator 6. To do this, we need to find out what number multiplied by the denominator gets you six. If you set up an equation, you would get: [tex]2*x=6[/tex] for 2 and [tex]3*x=6[/tex] for 3. Solve the first equation and you would get x=3. Solve the second equation and you would get x=2. Now, multiply the whole fraction with "x", according to its equation. You would get the new equation:[tex] \frac{1}{2} * 3/3 = ?[/tex] for 1/2 and [tex] \frac{1}{3} * 2/2 = ?[/tex] You would get the fractions: [tex]3/6[/tex] and [tex]2/6[/tex] Do not simplify yet. You must add them up then simplify. If you created a equation, you would get[tex] \frac{3}{6} + \frac{2}{6} [/tex] and you would get the answer: [tex] \frac{5}{6} [/tex] of an hour.
Now add all the hours together.
First, you add the hour from Wednesday [tex]1+[/tex]
Then you add the hour combined from Monday and Thursday [tex]1 + 1 + [/tex]
Last, you add the time combined from Tuesday and Friday [tex]1+1+ \frac{5}{6} [/tex]
If you added up all the time, you would get [tex]2 \frac{5}{6} [/tex] of an hour and that is your answer.
