One plane at 520 feet is ascending at a rate of 40 feet per minute, while another plane at 3800 feet is descending at a rate of 120 feet per minute. how long will it take the two lanes to be at the same altitude?
Plane A 520 feet vertical rise 40 feet/min plane B 3800 feet vertical dip 120 feet per minute. vertically the speeds are 40 feet / minute & 120 feet /minute. 120 + 40 = 160 feet per minute. the distance between them = 3800 -520 =3280 feet t= d/r 3280/160 t = 20.5 minutes. they will be at the same altitude.
