Respuesta :

carlosego
First we rewrite the functions:
 y = 2x
 y = x ^ 10
We note that the second function always has values of y greater than the first function. However, there is a value of x for which the first function is greater.
 For x = 1 we have:
 y = 2 (1) = 2
 y = (1) ^ 10 = 1
 We note that:
 2> 1
 Answer: 
 Yes, the value of function y = 2x eventually exceed the value of function y = x ^ 10.
thaovtp1407

Answer:

Yes

Step-by-step explanation:

Allow me to revise your question for a better understanding

y = 2x

y = [tex]x^{10}[/tex]

Any exponential function with a base bigger than 0 smaller than 1 will eventually be exceeded by any polynomial function. Let me give one example for this situation.

Let x = [tex]\frac{1}{2}[/tex], we have:

  • y = 2x = 2*[tex]\frac{1}{2}[/tex] = 1
  • y = [tex]x^{10}[/tex] =  [tex]\frac{1}{2} ^{10} = \frac{1}{1024}[/tex]

Obviously, y = [tex]x^{10}[/tex] <y = 2x  

Hope it will find you well.

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