Set up 2 variables:
x = larger number
y = smaller number
Set up equations:
[tex]x + y = 44[/tex]
[tex]3y = x[/tex]
Solve by substituting. I will use the x already given to us (in second equation) to substitute in 1st equation (x = 3y):
[tex]3y + y = 44[/tex]
[tex]4y = 44[/tex]
[tex]y = 11[/tex]
Plug it back into 2nd equation to solve for x:
[tex]3y = x[/tex]
[tex]3(11) = x = 33[/tex]
So, our two values are: x = 33 and y = 11.
We can check, x + y = 33 + 11 does equal 44 and 33 times is 3 times larger than 11. So, the initial criteria work out and we are right.
