Respuesta :
density of maple syrup = 1.325 g/ml
1000 ml contains 1325 g of maple syrup
In 100 g of maple syrup - 67 mg of Ca ions
Therefore in 1325 g of maple syrup - 67 mg /100g * 1325 g
= 887.75 mg of Ca
this means in 1000 ml - 887.75 mg of Ca
molar mass of Ca - 40 g/mol
therefore number of moles in 1000 ml - 0.88775 g /40 g/mol
molarity of Ca - 0.022 mol/dm³
1000 ml contains 1325 g of maple syrup
In 100 g of maple syrup - 67 mg of Ca ions
Therefore in 1325 g of maple syrup - 67 mg /100g * 1325 g
= 887.75 mg of Ca
this means in 1000 ml - 887.75 mg of Ca
molar mass of Ca - 40 g/mol
therefore number of moles in 1000 ml - 0.88775 g /40 g/mol
molarity of Ca - 0.022 mol/dm³
Explanation:
As density is mass divided by volume. And, it is given that mass of maple syrup is 100.00 g and its density is 1.325 g/ml.
Hence, volume of this maple syrup will be calculated as follows.
Volume = [tex]\frac{mass}{density}[/tex]
= [tex]\frac{100 g}{1.325 g/ml}[/tex]
= 75.47 ml
or, = 0.07547 L (as 1 L = 1000 ml)
Also, number of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
It is given that mass of calcium present in maple syrup is 67 mg and molar mass of calcium is 40 g/mol.
Hence, calculate the number of moles of [tex]Ca^{2+}[/tex] ions as follows.
number of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{67 mg}{40 g/mol}[/tex]
= 1.675 mol
As molarity is the number of moles present in liter of solution. Hence, calculate the molarity of calcium in maple syrup as follows.
Molarity = [tex]\frac{\text{no. of moles}}{volume}[/tex]
= [tex]\frac{1.675 mol}{0.07547 L}[/tex]
= 22.19 M
Therefore, we can conclude that molarity of calcium in maple syrup is 22.19 M.
