Answer:
(A)[tex]x^2+y^2-10x-12y+60=0[/tex]
Step-by-step explanation:
The standard form of the equation of a circle is given as:
[tex](x-5)^2+(y-6)^2=1[/tex]
Simplifying the above given equation, we get
[tex]x^2+25-10x+y^2+36-12y=1[/tex]
[tex]x^2+y^2-10x-12y+36+25=1[/tex]
[tex]x^2+y^2-10x-12y+61=1[/tex]
[tex]x^2+y^2-10x-12y+60=0[/tex]
which is the required general form of the equation.
Hence, option A is correct.
