Respuesta :
Let
Point 1 ----------> (5, 2)
Point 2 ----------> (–6, 2)
we know that
the distance between two points it is calculated with the formula
d=√[(y2-y1)²+(x2-x1)²]
then
d=√[(2-2)²+(-6-5)²]
d=√[(0)²+(-11)²]
d=√[121]
d=√121-----------> d=11 units
the answer is 11 units
Point 1 ----------> (5, 2)
Point 2 ----------> (–6, 2)
we know that
the distance between two points it is calculated with the formula
d=√[(y2-y1)²+(x2-x1)²]
then
d=√[(2-2)²+(-6-5)²]
d=√[(0)²+(-11)²]
d=√[121]
d=√121-----------> d=11 units
the answer is 11 units
The length of the segment formed by the two given endpoints with coordinates coordinates (5, 2) and (–6, 2) is;
d = 11
Formula for distance between two coordinates is given as;
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
We are given the coordinates (5, 2) and (–6, 2).
This means that;
x₁ = 5 and x₂ = -6
y₁ = 2 and y₂ = 2
Thus;
d = √[(-6 - 5)² + (2 - 2)²]
d = √(121 + 0)
d = √121
d = 11
In conclusion, the length of the segment formed by the two given endpoints is; d = 11
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