In order to find height (h), tan20 = h/26
[tex]h = 26 \tan(20) = 9.46[/tex]
Now for the left part of base (b1), where b2 = 26 and entire base (b) = b1+b2
[tex] \tan(36) = h \div b1 \\ b1 = 9.46 \div \tan(36) = 13.03[/tex]
So b = 13.03+26 = 39.03
Now Area (A) = 1/2bh = 1/2 (39.03)(9.46)
A = 184.59
