Answer:
The probability is [tex]P=\frac{5}{9}[/tex]
Step-by-step explanation:
Marvin has to randomly choose between 3 transport options.
Since the choice is random, then the probability of choosing any of the three options is the same.
The probability of teleportation in the first attempt is:
[tex]P_t = \frac{1}{3}[/tex]
So, the probability that you do not teleport is
[tex]q = 1-p\\\\q = 1-\frac{1}{3}\\\\q = \frac{2}{3}[/tex]
The probability that Marvin does not teleport when going to work and Marvin does not teleport when he returns from work is:
[tex]P = \frac{2}{3} * \frac{2}{3}\\\\P = \frac{4}{9}.[/tex]
Therefore the probability of teleportation at least once is:
[tex]P= 1-\frac{4}{9}\\\\P = \frac{5}{9}[/tex]
