Respuesta :

css0174217
(6,-1)
Multiply each equation by the value that makes the coefficients of xx opposite.(−3)⋅(2x+6y)=(−3)(6)(-3)⋅(2x+6y)=(-3)(6)(2)⋅(3x−2y)=(2)(20)(2)⋅(3x-2y)=(2)(20)Simplify.−6x−18y=−18-6x-18y=-186x−4y=406x-4y=40Add the two equations together to eliminate xx from the system.Divide each term by −22-22 and simplify.Tap for more steps...y=−1y=-1Substitute the value found for yy into one of the original equations, then solve for xx.Tap for more steps...x=6x=6The solution to the independent system of equations can be represented as a point.(6,−1)

Answer:

solution is (6,-1)

Step-by-step explanation:

[tex]2x + 6y = 6[/tex]

[tex]3x – 2y = 20[/tex]

WE use elimination method to solve for x  and y

Multiply the second equation by 3

[tex]3x – 2y = 20[/tex] times 3

[tex]9x – 6y = 60[/tex]

[tex]2x + 6y = 6[/tex] , add both equations

------------------------------

[tex]11x = 66[/tex]

Divide both sides by 11

[tex]x=6[/tex]

Plug in 6 for x in first equation

[tex]2x + 6y = 6[/tex]

[tex]2(6) + 6y = 6[/tex]

[tex]12 + 6y = 6[/tex], subtract 12 on both sides

[tex]6y = -6[/tex]

divide both sides by 6

[tex]y=-1[/tex]

[tex]x=6  \ and \ y= -1[/tex]

Otras preguntas