The slope of a line perpendicular to the line with equation y = 4x + 5 will be, [tex]-\frac{1}{4}[/tex].
What is a slope of a straight line?
A straight line is a combination of endless points joined on both sides of the point.
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
The slope 'm' of any straight line is given by:
The given equation in the problem is;
y = 4x + 5
The slope of the given equation is found from the standard equation of the straight line as;
y=mx+c
On comparing, we get, m = 4.
The perpendicular line slopes are reciprocals with the negative sign of each other.
Hence, the slope of a line perpendicular to the line with equation y = 4x + 5 will be, [tex]-\frac{1}{4}[/tex]
Learn more about the slope of the straight line refer;
brainly.com/question/3493733
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