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For the balanced equation shown below, how many moles of O2 will react with 0.3020 moles of CO2?
2C2H5OH + 6O2 → 4CO2 + 6H2O

0.151 moles O2


0.201 moles O2


0.302 moles O2


0.453 moles O2

Respuesta :

Dejanras
Answer is: 0,453  moles of oxygen will react with 0.3020 moles of carbon(IV) oxide.
n(CO₂) = 0,302 mol.
From chemical reaction: n(CO₂) : n(O₂) = 4 : 6.
n(O₂) = 6 · 0,302 mol ÷ 4.
n(O₂) = 0,453 mol.
n - amount of substance.

Answer : The number of moles of [tex]O_2[/tex] react will be, 0.453 moles

Solution : Given,

Moles of [tex]CO_2[/tex] = 0.3020 moles

The balanced chemical reaction is,

[tex]2C_2H_5OH+6O_2\rightarrow 4CO_2+6H_2O[/tex]

From the balanced reaction, we conclude that

As, 4 moles of [tex]CO_2[/tex] produces form 6 moles of [tex]O_2[/tex]

So, 0.3020 moles of [tex]CO_2[/tex] produces from [tex]\frac{6}{4}\times 0.3020=0.453moles[/tex] of [tex]O_2[/tex]

Therefore, the number of moles of [tex]O_2[/tex] react will be, 0.453 moles

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