We have the following functions:
f (x) = sin x
g (x) = cos x
The first thing we must do in this case is the composition of functions:
f (g (x))
By making the composition we have:
f (g (x)) = sin (cos x)
We evaluate for x = pi / 2:
f (g (pi / 2)) = sin (cos (pi / 2))
f (g (pi / 2)) = sin (0)
f (g (pi / 2)) = 0
Answer:
f (g (pi / 2)) = 0
