Answer:
Answer is (2log2 + 2log3 + 2logx + 2logy + 2logz)
Step-by-step explanation:
log4(3xyz)²
= log4 + log(3xyz)²
= log4 + 2log(3xyz)
= log(2)² + 2[log3 + logx + logy + logz]
= 2log2 + 2log3 + 2logx + 2logy + 2logz
