Respuesta :

1. Gypsum has the formula as CaSO₄.2H₂O. Hence, CaSO₄ is bound with two H₂O. CaSO₄ has 1 Ca atom, 1 S atom and 4 O atoms. 2H₂O have 4 H atoms and 2 O atoms.
Hence,
      total Ca atoms = 1
      total S atoms = 1
      total O atoms = 4 + 2 = 6
      total H atoms = 4
      total number of atoms = 1 + 1 + 6 + 4 = 12

2. Cellulose has the formula as C₆H₇O₂(OH)₃. But there are 2 molecules. Hence, to find total atoms in each element, number of atoms should be multiplied by 2 .The elements of the cellulose are C, H, and O. Hence,
      total C atoms = 6 x 2 = 12
      total O atoms = (2 + 3) x 2 = 10
      total H atoms = (7 + 3) x 2 = 20
      total number of atoms = 12 + 10 + 20 = 42

3. The formula of the antiperspirant is Al₂Cl(OH)₅. It has Al, Cl, O and H as the elements. Hence, the number of atoms in each element can be found as follows;
      total Al atoms = 2
      total Cl atoms = 1
      total H atoms = 1 x 5 = 5
      total O atoms = 1 x 5 = 5
      total number of atoms = 2 + 1 + 5 + 5 = 13

Explanation:

  • Formula of gypsum is [tex]CaSO_{4}.2H_{2}O[/tex]. Therefore, total number of atoms of each element present in gypsum are as follows.

Number of Ca atom = 1

Number of S atom = 1

Number of O atom = 6

Number of H atom = 2

  • Formula of cellulose is [tex]C_{6}H_{7}O_{2}(OH)_{3}[/tex]. Therefore, total number of atoms of each element present in 2 molecules of cellulose are as follows.

Number of Ca atom = 2 × 6 = 12

Number of H atom = 2 × 10 = 20

Number of O atom = 2 × 5 = 10

  • Formula of antiperspirant is [tex]Al_{2}Cl(OH)_{5}[/tex]. Therefore, total number of atoms of each element present antipersiperant are as follows.

Number of Al atom = 2

Number of Cl atom = 1

Number of O atom = 5

Number of H atom = 5