Respuesta :
[tex]\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
\begin{array}{llcccl}
y = & 1x^2& +6x& +7\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad
\left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left( -\cfrac{6}{2(1)}~~,~~7-\cfrac{6^2}{4(1)} \right)\implies (-3~~,~~7-9)\implies (-3~~,~~-2)[/tex]
Answer:
below the x axis
Step-by-step explanation:
i took the test
