[tex]\bf \begin{array}{ccll}
\stackrel{sodium}{grams}&\stackrel{soda}{liters}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
3&\frac{1}{2}\\\\
g&\frac{2}{3}
\end{array}\implies \cfrac{3}{g}=\cfrac{\quad \frac{1}{2}\quad }{\frac{2}{3}}\implies \cfrac{3}{g}=\cfrac{1}{2}\cdot \cfrac{3}{2}\implies \cfrac{3}{g}=\cfrac{3}{4}
\\\\\\
12=3g\implies \cfrac{12}{3}=g\implies 4=g[/tex]
