In a 30-60-90 triangle, what is the length of the hypotenuse when the shorter leg is 7 in?
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The length of the hypotenuse is 14in
Given a 30-60-90 triangle where:
Length of the shorter leg = 5cm (adjacent)
The hypotenuse is what we need..
[tex]cos \theta = \frac{adj}{hyp} \\ [/tex]
Substitute the given parameters
[tex]cos 60 = \frac{7}{h}\\ h =\frac{7}{cos 60}\\ h = \frac{7}{0.5}\\ h = 14in\\ [/tex]
Hence the length of the hypotenuse is 14in
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