Respuesta :

It's the first one.

To reflect the function [tex]f(x)=8( \frac{1}{4})^{x}[/tex] about the y-axis, we write[tex]g(x)=8( \frac{1}{4})^{-x}[/tex]. 

You can then substitute values into both functions. Remember that something to the power zero is equal one, so for either function evaluated at x = 0, the answer is 8.

Answer:

Table 1

Step-by-step explanation:

We have the function [tex]f(x)=8(\frac{1}{4})^{x}[/tex].

Now, the function g(x) is obtained by reflecting f(x) across y-axis.

i.e. g(x) = f(-x)

i.e. [tex]g(x)=8(\frac{1}{4})^{-x}[/tex]

So, substituting the values of x in f(x) or g(x), we will discard some options.

2. For x=0, the value of [tex]f(0)=8(\frac{1}{4})^{0}[/tex] i.e. f(0) = 8.

As in table 2, f(0) = 0 is given, this is not correct.

3. For x=0, the value of [tex]g(0)=8(\frac{1}{4})^{-0}[/tex] i.e. g(0) = 8.

As in table 3, g(0) = -8 is given, this is not correct.

4. For x=0, the value of [tex]g(0)=8(\frac{1}{4})^{-0}[/tex] i.e. g(0) = 8.

As in table 3, g(0) = 0 is given, this is not correct.

Thus, all the tables 2, 3 and 4 do not represent these functions.

Hence, table 1 represents f(x) and g(x) as the values are satisfied in this table.