Question 1:
- both squared roots are multiplied by 4, therefore you can regroup: 4·(√11·√10)
- since they are both squared roots, you can multiply the two numbers: 4·√(11·10)
- therefore the answer is: 4·√110
Question 2:
- first thing, you need to factorize the number: 24=2³·3
- then, highlight the exponents multipes of 3: ∛(2³·3·a^9·a·b^6)
- now you can take outside the cubic root everything that has an exponent multiple of 3, dividing the exponents by 3: 2·a³b²·∛3·a
