The amount of heat Q absorbed by a substance is related to its increase of temperature [tex]\Delta T[/tex] by the following relationship:
[tex]Q=mC_s \Delta T[/tex]
where m is the mass of the substance and [tex]C_s [/tex] is its specific heat.
Using [tex]m=500 g=0.5 kg[/tex], [tex]Q=3.25 \cdot 10^3 J[/tex] and [tex]\Delta T=50 K[/tex], we can find the specific heat of the substance by re-arranging the formula:
[tex]C_s = \frac{Q}{m \Delta T} = \frac{3.25 \cdot 10^3 J}{(0.5 kg)(50 K)}=130 J/(KgK) [/tex]
and looking at the table of specific heat values for various substance, we find that this value corresponds to lead.
