Respuesta :
The balance equation is :
SO2 + CaO → CaSO3
1.
(2100 tons) x (0.025 S) / (32.0655 g S/mol) x (1 mol SO2 / 1 mol S) x
(1 mol CaO / 1 mol SO2) x (56.0778 g CaO/mol)
= 91.81 tons CaO
2. (2100 tons) x (0.025 S) x (907185 g/ton) / (32.0655 g S/mol) x (1 mol SO2 / 1 mol S) x (1 mol CaSO3 / 1 mol SO2) x (120.1422 g CaSO3/mol)
= 1.784 x 10^8 g CaSO3
SO2 + CaO → CaSO3
1.
(2100 tons) x (0.025 S) / (32.0655 g S/mol) x (1 mol SO2 / 1 mol S) x
(1 mol CaO / 1 mol SO2) x (56.0778 g CaO/mol)
= 91.81 tons CaO
2. (2100 tons) x (0.025 S) x (907185 g/ton) / (32.0655 g S/mol) x (1 mol SO2 / 1 mol S) x (1 mol CaSO3 / 1 mol SO2) x (120.1422 g CaSO3/mol)
= 1.784 x 10^8 g CaSO3
Although your question is incomplete I have provide more general answer is provided
The Reaction equation between sulfur dioxide and solid calcium oxide :
[tex]SO_{2}_{(g)} + CaO_{(s)} ---> CaSO_{3}_{(s)}[/tex]
Given that your question is vague I have provided the reaction equation between the Sulphur dioxide and calcium oxide, and the chemical conversion equation of Sulphur to Sulphur dioxide ( gas )
conversion of Sulphur to Sulphur dioxide
= [tex]S_{(s)} + O_{(2)}_{(g)} ----> SO_{2}_{(g)}[/tex]
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