Respuesta :
Based on your problem above, we have to balance the equation in order to get the product.
From your given, ΔH∘f of SrCO3(s)
The balanced equation is:
Sr(s) + C(s) + 3/2 O2(g) -> SrCO3(s)
From your given, ΔH∘f of SrCO3(s)
The balanced equation is:
Sr(s) + C(s) + 3/2 O2(g) -> SrCO3(s)
Answer:
[tex]Sr(s)+C(s)+ 3/2O_{2}(g)\rightarrow SrCO_{3}(s)[/tex]
Explanation:
The standard enthalpy of formation (ΔH°f) is defined as the enthalpy change which accompanies the formation of 1 mole of a compound from its constituent elements all of which are in their standard states i.e. either solid (s), liquid (l) , gas (g) or the aqueous phase (aq).
Strontium carbonate (SrCO3) contains 3 elements:
-Strontium (Sr) where the standard state is solid(s)
- Carbon (C) where the standard state is again a solid (s)
- oxygen (O) where the standard state is the gas phase (g)
The balanced chemical equation for the standard enthalpy of formation (ΔH°f) for SrCO3 would be:
[tex]Sr(s)+C(s)+ 3/2O_{2}(g)\rightarrow SrCO_{3}(s)[/tex]