What is the total pressure in a 6.00-l flask which contains 0.127 mol of h2(g) and 0.288 mol of n2(g) at 20.0°c?

Question

07-03-2018
Chemistry

contestada

What is the total pressure in a 6.00-l flask which contains 0.127 mol of h2(g) and 0.288 mol of n2(g) at 20.0°c?

Respuesta :

Otras preguntas

In a national survey of 6700 teens, 81% of teens between the ages of 12 and 17 said they use the Internet to e-mail friends or relatives. About how many teens i

An unknown disease or a well-known disease that suddenly becomes harder to control is called A. a pathogen. B. an emerging disease. C. an antibiotic. D. a vi

What is the male sex organ

Name the corresponding part if RST WXY. ∠ S =

_____ acts as a messenger between DNA and the ribosomes. A. Cytosine B. Thymine C. RNA D. Uracil

Specialized structures that allow mangroves to get oxygen in soil that is usually anaerobic are called (2 points) rhizomes. pores. runners. pneumatophores.

The president pro tempore of the Senate is what?

In active transport, molecules move from areas of _______ concentration to areas of ______ concentration and require _______.

what is the area of the combined rectangle below? 20yd would be the base, 12yd would be the base, 5yd would be the height, 3yd would be the height. (A) 136 squa

Edufirst Edufirst · Answer 1 · 2018-03-17T18:23:51+01:00

Edufirst Edufirst

17-03-2018

Answer: 1.66 atm

Data:

P = ?
V = 6.00 liter
n1 = 0.127 mol of H2(g)
n2 = 0.288 mol of N2(g)
T = 20.0°C

Formula:

PV = n RT

Solution:

1) Conversion of units:

= 20 + 273.15 K = 293.15 K

2) n = n1 + n2 = 0.127 mol + 0.288 mol = 0.415 mol

3) PV = nRT => P = nRT / V

R = 0.0821 atm*liter / (K*mol)

P = 0.415 mol * 0.0821 atm * liter / (K*mol) * 293.15 K / 6 liter = 1.66 atm

Answer: 1.66 atm

Answer Link