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A buffer contains significant amounts of ammonia and ammonium chloride. part a write an equation showing how this buffer neutralizes added acid (hi).

Respuesta :

Hello!

When HI is added, the buffer reacts in the following way:

1) Neutralizing of the Acid:

HI + NH₄OH → NH₄I + H₂O

2) Dissociation of the salt of a weak acid:

NH₄I → NH₄⁺(aq) + I⁻ (aq)

3) Dissociation of a weak acid to form H₃O⁺ (very little):

NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺

This series of reactions show how the adding of a strong Acid can be neutralized by the buffer, releasing instead very little amounts of Hydronium ions.

Have a nice day!

The equation showing the buffer neutralizes acid is, when Hi is added, the reaction is:

[tex]\rm HI + NH_4OH = NH_4I + H_2O[/tex]

What is a buffer solution?

A buffer solution is made up of a weak acid and the conjugate base.

There are the processes following for neutralization of the buffer solution

a. Neutralization of the acid:

[tex]\rm HI + NH_4OH = NH_4I + H_2O[/tex]

b. Dissociation of salt of the weak acid:

[tex]\rm NH_4I = NH_4^+(aq) + I^- (aq)[/tex]

c. Dissociation of weak acid to form [tex]\rm H_3O^+[/tex]

[tex]\rm NH_4^+ + H_2O = NH_3 + H_3O^+[/tex]

Thus, these processes show that, on adding a strong acid, the buffer solution can be neutralized.

Learn more about buffer, here:

https://brainly.com/question/24188850