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When HI is added, the buffer reacts in the following way:
1) Neutralizing of the Acid:
HI + NH₄OH → NH₄I + H₂O
2) Dissociation of the salt of a weak acid:
NH₄I → NH₄⁺(aq) + I⁻ (aq)
3) Dissociation of a weak acid to form H₃O⁺ (very little):
NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺
This series of reactions show how the adding of a strong Acid can be neutralized by the buffer, releasing instead very little amounts of Hydronium ions.
Have a nice day!
When HI is added, the buffer reacts in the following way:
1) Neutralizing of the Acid:
HI + NH₄OH → NH₄I + H₂O
2) Dissociation of the salt of a weak acid:
NH₄I → NH₄⁺(aq) + I⁻ (aq)
3) Dissociation of a weak acid to form H₃O⁺ (very little):
NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺
This series of reactions show how the adding of a strong Acid can be neutralized by the buffer, releasing instead very little amounts of Hydronium ions.
Have a nice day!
The equation showing the buffer neutralizes acid is, when Hi is added, the reaction is:
[tex]\rm HI + NH_4OH = NH_4I + H_2O[/tex]
What is a buffer solution?
A buffer solution is made up of a weak acid and the conjugate base.
There are the processes following for neutralization of the buffer solution
a. Neutralization of the acid:
[tex]\rm HI + NH_4OH = NH_4I + H_2O[/tex]
b. Dissociation of salt of the weak acid:
[tex]\rm NH_4I = NH_4^+(aq) + I^- (aq)[/tex]
c. Dissociation of weak acid to form [tex]\rm H_3O^+[/tex]
[tex]\rm NH_4^+ + H_2O = NH_3 + H_3O^+[/tex]
Thus, these processes show that, on adding a strong acid, the buffer solution can be neutralized.
Learn more about buffer, here:
https://brainly.com/question/24188850