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Answer is: 9 grams of water are needed to react.
Chemical reaction: Li₂O + H₂O → 2LiOH.
m(Li₂O) = 15 g.
n(Li₂O) = m(Li₂O) ÷ M(Li₂O).
n(Li₂O) = 15 g ÷ 30 g/mol.
n(Li₂O) = 0,5 mol.
From chemical reaction: n(Li₂O) : n(H₂O) = 1 : 1.
n(H₂O) = 0,5 mol.
m(H₂O) = 0,5 mol · 18 g/mol.
m(H₂O) = 9 g.

Answer:

9.04 g of [tex]H_{2}O[/tex] are needed to react

Explanation:

According to balanced equation, 1 mol of [tex]H_{2}O[/tex] reacts with 1 mol of [tex]Li_{2}O[/tex]

Molar mass of [tex]Li_{2}O[/tex] = 29.9 g/mol

Number of moles = (mass)/(molar mass)

So, 15.0 g of [tex]Li_{2}O[/tex] = [tex]\frac{15.0}{29.9}[/tex] moles of [tex]Li_{2}O[/tex]

So, moles of [tex]H_{2}O[/tex] are needed to react = [tex]\frac{15.0}{29.9}[/tex] moles

Molar mass of  [tex]H_{2}O[/tex] = 18.02 g/mol

So, mass of [tex]H_{2}O[/tex] are needed to react = [tex]\frac{15.0}{29.9}\times 18.02g=9.04g[/tex]

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