Respuesta :
Answer: The mass of sucrose is 34.23 g
Explanation:
Molarity is defined as the number of moles present in one liter of solution.
Mathematically,
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
Or,
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Molarity of solution = 0.200 M
Molar mass of sucrose = 342.3 g/mol
Volume of solution = 500 mL
Mass of sucrose = ? g
Putting values in above equation, we get:
[tex]0.200mol/L=\frac{\text{Mass of sucrose}\times 1000}{342.3g/mol\times 500mL}\\\\\text{Mass of sucrose}=34.23g[/tex]
Hence, the mass of sucrose is 34.23 g
