5x^2+2x-12=0 is a quadratic equation. For any ax^2 + bx + c = 0, the solution can be found by completing the square to find the equations
x=(-b+sqrt(b^2-4ac))/2a and x=(-b-sqrt(b^2-4ac))/2a
Substituting using the equation 0=5x^2+2x-12
x=(-2+sqrt(2^2-4(5)(-12)))/(2(5)) and x=(-2+sqrt(2^2-4(5)(-12)))/(2(5))
Since the sqrt(244) is a real number, there are two real solutions.
