Respuesta :
The answer is 81 decibels
To solve this, we will use the formula : dB = 10 x log (Isig/Iref)
terms will be:dB= decibels,
Isig = signal's intensity
Iref= softest sound's intensity which is 10^-12.
So the solutions is,dB = 10 x log (1.25 x 10–4 / 10^-12 )
= 80.97 decibels
=81 decibels
To solve this, we will use the formula : dB = 10 x log (Isig/Iref)
terms will be:dB= decibels,
Isig = signal's intensity
Iref= softest sound's intensity which is 10^-12.
So the solutions is,dB = 10 x log (1.25 x 10–4 / 10^-12 )
= 80.97 decibels
=81 decibels
Answer:
1. B) logb(q^2t^8)
2. D) None of these (it is actually log (x^4/(x+2)^6) :D)
3. B) log5(7)+5log5(a)
4. C) 6.209
5. A) 81 decibels
Step-by-step explanation:
trust me bro