Respuesta :
Pythagoras theorem
[tex] {x}^{2} = {1}^{2} + {1}^{2} \\ {x}^{2} = 1 + 1 \\ {x}^{2} = 2 \\ x = \sqrt{2} = 1.41[/tex]
[tex] {x}^{2} = {1}^{2} + {1}^{2} \\ {x}^{2} = 1 + 1 \\ {x}^{2} = 2 \\ x = \sqrt{2} = 1.41[/tex]
Answer:
The length of the hypotenuse of the isosceles right triangle with leg of length unit is:
√2 units.
Step-by-step explanation:
Let a and b denote the leg of a right triangle and c denote the hypotenuse of the right triangle.
Now we apply the Pythagorean Theorem as:
[tex]c^2=a^2+b^2[/tex]
Now as triangle is isosceles.
Hence, a=b=1 unit
[tex]c^2=1^2+1^2\\\\c^2=2\\\\c=\sqrt{2}[/tex]
Hence, the length of the hypotenuse is:
√2 units.