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The length of a rectangle is represented by the function L(x) = 6x. The width of that same rectangle is represented by the function W(x) = 4x2 − 3x + 8. Which of the following shows the area of the rectangle in terms of x?

Respuesta :

hisroyal1
Length of the rectangle, L(x) = 6x
Width of the rectangle, W(x) = 4x² - 3x + 8

Area of a rectangle = Length * Width
Therefore, Area od the rectangle = 6x (4x² - 3x + 8)

= (4x² · 6x) - (3x · 6x) + (8 · 6x)

= 24x³ - 18x² + 48x
AlpenGlow
We know that the area of a rectangle can be computed by multiplying the length times the width. 

P = L X W

Now taking into account the given, we can say that:
[tex](L.W)(x) = (6x)(4 x^{2} - 3x + 8)[/tex]

Now let's simplify the expression by doing the operation and you will have this as your result:
[tex](L.W)(x) = 24x^{3} - 18x^{2} + 48x[/tex]

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